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Two vectors vecA and vecB are such that ...

Two vectors `vecA` and `vecB` are such that `vecA+vecB=vecA-vecB`. Then

A

`vec(a).vec(b)+vec(b).vec(c)+vec(c).vec(a)=0`

B

`vec(a)xxvec(b)=vec(b)xxvec(c)=vec(c)xxvec(a)`

C

`vec(a).vec(b)=vec(b).vec(c)=vec(c).vec(a)`

D

`vec(a)xxvec(b)+vec(b)xxvec(c)+vec(c)xxvec(a)=vec(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
Area of triangle `=1/2 (vec(a)xxvec(b))=1/2(bxxvec(c))=1/2(vec(c)xxvec(a))`
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