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Two particle A and B are moving in XY-pl...

Two particle A and B are moving in XY-plane. Their positions vary with time t according to relation
`x_(A)(t)=3t, x_(B)(t)=6`
`y_(A)(t)=t, y_(B)(t)=2+3t^(2)`
The distance between two particle at `t=1` is :

Text Solution

Verified by Experts

The correct Answer is:
B
`l=sqrt((100-2t)^(2)+(200-4t)^(2))`
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Knowledge Check

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