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A body is released from the top of a smo...

A body is released from the top of a smooth inclined plane of inclination `theta`. It reaches the bottom with velocity `v`. If the angle of inclina-tion is doubled for the same length of the plane, what will be the velocity of the body on reach ing the ground .

A

v

B

2v

C

`[2 cos theta]^(1//2)v`

D

`[2 sin theta]^(1//2)v`

Text Solution

Verified by Experts

The correct Answer is:
C

by III EOM,
`v^(2)=O^(2)+2(g sin theta)s`
`v=sqrt(2gs sin theta)`,
`v=sqrt(2gs sin 2theta)=sqrt(2gs 2sin theta cos theta)`
`v=sqrt(2gs sin theta)sqrt(2cos theta)=vxx(2cos theta)^(1//2)`
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