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A particle moves on a circular path of r...

A particle moves on a circular path of radius 'r'. It completes one revolution in 40s. Calculate distances displacement in 2 min 20 s.

Text Solution

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`t = 2min 20 sec = 120 + 20 = 140 sec`
after each complete rotation, displacement becomes zero.
Number of rotation `= (140)/(40) = 3 + (1)/(2) `
` therefore ` displacement in `(1)/(2)` rotation = 2r
( displacement for 3 rotation =0)
Distance in `3 + (1)/(2)` rotation = `3xx 2pi r + pi r = 7pi r`
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