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Position of particle moving along x-axis...

Position of particle moving along x-axis is given as `x=2+5t+7t^(2)` then calculate :

A

Velocity `(i.e(dx)/(dt))` of particle

B

Initial velocity`(i.e(dx)/(dt)" att"=0)`

C

Velocity at `t=2sec`

D

Accleration`(i.e(d^(2)x)/(dt^(2)))` of particle

Text Solution

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The correct Answer is:
A, B, C, D
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Knowledge Check

  • The position of a particle moving along a. straight line is given by x = 2 - 5t + t ^(3) The acceleration of the particle at t = 2 sec. is ...... Here x is in meter.

    A
    `12m/s ^(2)`
    B
    `8m//s^(2)`
    C
    `7m//s^(2)`
    D
    None of these

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