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A particle of mass m is moving in a hori...

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to -`(K//r^(2))`. Where K is constant. What is the total energy of the particle?

A

`-K//2r`

B

`K/4r`

C

`K/r`

D

None

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The correct Answer is:
A
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Knowledge Check

  • A particle of mass m moves on a circular path of r radius . Its centripetal acceleration is kt^(2) where k is a constant and t is time , Express power as function of t .

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