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Two paricles of equal mass m go round a ...

Two paricles of equal mass `m` go round a circle of radius R under the action of their mutual gravitional attraction. The speed of each particle is

A

`(1)/(2R)sqrt((1)/(Gm)`

B

`sqrt((Gm)/(2R))`

C

`(1)/(2)sqrt((Gm)/(R))`

D

`sqrt((4Gm)/(R))`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • Two particles of equal mass m move around a circle of radius R under the influence of their mutual gravitational attraction, the speed of each particle with respect to their center of mass will be ..........

    A
    `sqrt((Gm)/(R))`
    B
    `sqrt((Gm)/(4R))`
    C
    `sqrt((Gm)/(3R))`
    D
    `sqrt((Gm)/(2R))`

  • Four particles, each of mass M and equidistant "from each other, move along a circle of radius R under the action of the mutual gravitational attraction. The speed of each particle is ......... (G = universal gravitational constant)

    A
    `sqrt((GM)/R (1+2sqrt2))`
    B
    `1/2sqrt((GM)/R (1+2sqrt2))`
    C
    `sqrt((GM)/R)`
    D
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  • Two particle which are initially at rest, move towards each other under the action of their internal alteration. If there speeds are v and 2v at any instant, then the speed of centre of mass of the system will be……….

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