The molecules having the same hybridization, shape and number of lone pairs of electrons are

Options

A. a. `SeF_(4), XeO_(2)F_(2)`
B. b. `SF_(4), XeF_(2)`
C. c. `XeOF_(4), TeF_(4)`
D. d. `SeCl_(4),XeF_(4)`

Explanation

To solve the question regarding which molecules have the same hybridization, shape, and number of lone pairs of electrons, we will analyze each option step by step.

### Step 1: Identify the Steric Number
The steric number (SN) is calculated using the formula:
\[ \text{SN} = \frac{\text{Number of valence electrons} + \text{Number of monovalent atoms}}{2} \]

### Step 2: Determine Hybridization
Based on the steric number, we can determine the hybridization:
- SN = 2 → sp
- SN = 3 → sp²
- SN = 4 → sp³
- SN = 5 → sp³d
- SN = 6 → sp³d²

### Step 3: Analyze Each Molecule
Let's analyze the given molecules:

1. **XeF4**:
- Valence electrons of Xe = 8
- Monovalent atoms (F) = 4
- SN = (8 + 4) / 2 = 6 → Hybridization = sp³d²
- Shape = Square planar (0 lone pairs)

2. **XeO2F2**:
- Valence electrons of Xe = 8
- Monovalent atoms (F) = 2
- SN = (8 + 2) / 2 = 5 → Hybridization = sp³d
- Shape = Seesaw (1 lone pair)

3. **SF4**:
- Valence electrons of S = 6
- Monovalent atoms (F) = 4
- SN = (6 + 4) / 2 = 5 → Hybridization = sp³d
- Shape = Seesaw (1 lone pair)

4. **XeF2**:
- Valence electrons of Xe = 8
- Monovalent atoms (F) = 2
- SN = (8 + 2) / 2 = 5 → Hybridization = sp³d
- Shape = Linear (3 lone pairs)

5. **TeF4**:
- Valence electrons of Te = 6
- Monovalent atoms (F) = 4
- SN = (6 + 4) / 2 = 5 → Hybridization = sp³d
- Shape = Seesaw (1 lone pair)

6. **SeCl4**:
- Valence electrons of Se = 6
- Monovalent atoms (Cl) = 4
- SN = (6 + 4) / 2 = 5 → Hybridization = sp³d
- Shape = Seesaw (1 lone pair)

### Step 4: Compare the Results
Now we compare the hybridization, shape, and lone pairs:
- **XeO2F2**: sp³d, Seesaw, 1 lone pair
- **SF4**: sp³d, Seesaw, 1 lone pair
- **TeF4**: sp³d, Seesaw, 1 lone pair
- **SeCl4**: sp³d, Seesaw, 1 lone pair

### Conclusion
The molecules that have the same hybridization (sp³d), shape (Seesaw), and number of lone pairs (1) are:
- **XeO2F2**
- **SF4**
- **TeF4**
- **SeCl4**

Thus, the correct answer is **option A**: XeO2F2 and SF4.