An organic compound 'X' on treatment with pyridinium chlorochromate in dichloromethane gives compound 'Y'. Compoun 'Y', reacts with `I_(2)` and alkali to form tri-iodomethane. The compound 'X' is `:`

Options

A. `C_(2)H_(5)OH`
B. `CH_(3)CHO`
C. `CH_(3)COCH_(3)`
D. `CH_(3)COOH`

Explanation

To solve the problem step by step, we will analyze the information provided and deduce the structure of compound 'X'.

### Step 1: Identify the reaction of compound 'X' with pyridinium chlorochromate (PCC).
- **PCC** is a mild oxidizing agent that typically converts alcohols to carbonyl compounds (aldehydes or ketones).
- Therefore, compound 'X' must be an alcohol because it is being oxidized to a compound 'Y' (which is a carbonyl compound).

### Step 2: Determine the nature of compound 'Y'.
- Since compound 'Y' is formed from the oxidation of an alcohol, it can either be an aldehyde or a ketone.
- The next part of the question states that compound 'Y' reacts with iodine (I2) and alkali to form triiodomethane (CHI3).
- Triiodomethane is formed from the reaction of iodine with a methyl ketone or an aldehyde that has at least one methyl group adjacent to the carbonyl.

### Step 3: Analyze the reaction of compound 'Y' with iodine and alkali.
- The reaction of an aldehyde (specifically, acetaldehyde, CH3CHO) with I2 and NaOH will yield triiodomethane (CHI3).
- This indicates that compound 'Y' must be acetaldehyde (CH3CHO).

### Step 4: Identify compound 'X'.
- Since compound 'Y' is acetaldehyde, we can deduce that compound 'X' must be ethanol (C2H5OH), which is the alcohol that gets oxidized to acetaldehyde by PCC.

### Conclusion:
- The compound 'X' is **ethanol (C2H5OH)**.

### Summary of Reactions:
1. **X (C2H5OH) + PCC → Y (CH3CHO)**
2. **Y (CH3CHO) + I2 + NaOH → CHI3 + by-products**

### Final Answer:
The compound 'X' is **C2H5OH (ethanol)**.

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