Home
Class 12
CHEMISTRY
An octahedral complex is formed when hyb...

An octahedral complex is formed when hybrid orbitals of the following type are involved

A

a. `sp^3`

B

b. `dsp^2`

C

c. `d^2sp^3`

D

d. `sp^3d^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the type of hybrid orbitals involved in the formation of an octahedral complex, we will analyze the options based on the principles of Valence Bond Theory (VBT) and the characteristics of octahedral complexes. ### Step-by-Step Solution: 1. **Understanding Octahedral Complexes**: - Octahedral complexes are formed when a central metal atom is surrounded by six ligands at the corners of an octahedron. 2. **Hybridization in Octahedral Complexes**: - According to Valence Bond Theory, octahedral complexes can exhibit two types of hybridization based on the involvement of d-orbitals: - **Inner Orbital Complexes**: These involve the hybridization of the d-orbitals from the inner shell of the metal. The hybridization here is **d²sp³**. - **Outer Orbital Complexes**: These involve the hybridization of the d-orbitals from the outer shell. The hybridization here is **sp³d²**. 3. **Identifying Ligands**: - The type of hybridization depends on the nature of the ligands: - **Strong Field Ligands**: These ligands can cause pairing of electrons in the d-orbitals, leading to the formation of inner orbital complexes (d²sp³). - **Weak Field Ligands**: These ligands do not cause pairing of electrons and lead to the formation of outer orbital complexes (sp³d²). 4. **Conclusion**: - Therefore, the hybrid orbitals involved in the formation of octahedral complexes are **d²sp³** for inner orbital complexes and **sp³d²** for outer orbital complexes. ### Final Answer: The hybrid orbitals involved in the formation of an octahedral complex are **d²sp³** and **sp³d²**.
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

Complete removal of both the axial ligands (along the z-axis) from an octahedral complex leads to which of the following splitting patterns? (relative orbital energies not on scale).

The bond angle formed by different hybrid orbitals are in the order

Knowledge Check

  • Ammonia molecule is formed by the following hybrid orbitals:

    A
    `dsp^2`
    B
    `sp^3`
    C
    `sp^3 d`
    D
    `d^2 sp`
  • Octahedral complexes involve the type of hybridization as

    A
    `sp^3`
    B
    `dsp^2`
    C
    `d^2sp^3`
    D
    `sp^3d`
  • Similar Questions

    Explore conceptually related problems

    Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at 25^@C ?

    In what respects do inner orbital octahedral complexes differ from outer orbital octahedral complexes

    An octahedral complex of Co^(3+) is diamagnetic . The hybridisation involved in the formation of the complex is :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :