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Which of the following expressions is co...

Which of the following expressions is correct for the rate of reaction given below?
` 5 Br^(-) (aq) +BrO_(3)^(-) (aq) + 6H^(+) (aq) to 3Br_2(aq) + 2H_2 O(l)`

A

`(Delta [Br^(-)])/(Delta t)=5 ( Delta [H^(+)])/( Delta t)`

B

`(Delta [Br^(-)])/(Delta t)=6/5 ( Delta [H^(+)])/( Delta t)`

C

`(Delta [Br^(-)])/(Delta t)=5/6 ( Delta [H^(+)])/( Delta t)`

D

`(Delta [Br^(-)])/(Delta t)=6 ( Delta [H^(+)])/( Delta t)`

Text Solution

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The correct Answer is:
To determine the correct expression for the rate of the given reaction: **Reaction:** \[ 5 \text{Br}^- (aq) + \text{BrO}_3^- (aq) + 6 \text{H}^+ (aq) \rightarrow 3 \text{Br}_2 (aq) + 2 \text{H}_2\text{O} (l) \] **Step 1: Write the Rate Expression** The rate of a reaction can be expressed in terms of the change in concentration of reactants and products over time. The general form is: \[ R = -\frac{1}{n} \frac{\Delta [A]}{\Delta t} \] where \( n \) is the stoichiometric coefficient of the reactant \( A \). **Step 2: Identify Stoichiometric Coefficients** From the balanced equation, we have: - For \( \text{Br}^- \): coefficient = 5 - For \( \text{BrO}_3^- \): coefficient = 1 - For \( \text{H}^+ \): coefficient = 6 - For \( \text{Br}_2 \): coefficient = 3 - For \( \text{H}_2\text{O} \): coefficient = 2 **Step 3: Write the Rate in Terms of Each Reactant and Product** Using the stoichiometric coefficients, we can write the rate expressions for each species: 1. For \( \text{Br}^- \): \[ R = -\frac{1}{5} \frac{\Delta [\text{Br}^-]}{\Delta t} \] 2. For \( \text{BrO}_3^- \): \[ R = -\frac{1}{1} \frac{\Delta [\text{BrO}_3^-]}{\Delta t} \] 3. For \( \text{H}^+ \): \[ R = -\frac{1}{6} \frac{\Delta [\text{H}^+]}{\Delta t} \] 4. For \( \text{Br}_2 \): \[ R = \frac{1}{3} \frac{\Delta [\text{Br}_2]}{\Delta t} \] 5. For \( \text{H}_2\text{O} \): \[ R = \frac{1}{2} \frac{\Delta [\text{H}_2\text{O}]}{\Delta t} \] **Step 4: Equate the Expressions** All these expressions represent the same rate \( R \), so we can set them equal to each other. For example, equating the rate expressions for \( \text{Br}^- \) and \( \text{H}^+ \): \[ -\frac{1}{5} \frac{\Delta [\text{Br}^-]}{\Delta t} = -\frac{1}{6} \frac{\Delta [\text{H}^+]}{\Delta t} \] From this, we can derive: \[ \frac{\Delta [\text{Br}^-]}{\Delta [\text{H}^+]} = \frac{5}{6} \] **Step 5: Check Each Expression** Now, we can check the expressions given in the question against our derived relationships. - The expression for \( \text{Br}^- \) in terms of \( \text{H}^+ \) should be: \[ \Delta [\text{Br}^-] = \frac{5}{6} \Delta [\text{H}^+] \] Thus, the correct expression for \( \Delta [\text{H}^+] \) in terms of \( \Delta [\text{Br}^-] \) would be: \[ \Delta [\text{H}^+] = \frac{6}{5} \Delta [\text{Br}^-] \] **Final Conclusion: Identify the Correct Expression** After analyzing the expressions, we can determine which one is correct based on the stoichiometric relationships derived from the rate expressions.

To determine the correct expression for the rate of the given reaction: **Reaction:** \[ 5 \text{Br}^- (aq) + \text{BrO}_3^- (aq) + 6 \text{H}^+ (aq) \rightarrow 3 \text{Br}_2 (aq) + 2 \text{H}_2\text{O} (l) \] **Step 1: Write the Rate Expression** The rate of a reaction can be expressed in terms of the change in concentration of reactants and products over time. The general form is: ...
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