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The unit of force in SI system is newton...

The unit of force in SI system is newton (N) and in CGS system is dyne. One newton is equal to 1 kg m `s^(-2)` and 1 dyne is equal to 1 g cm `s^(-2)`. How many dynes make one newton?

Text Solution

Verified by Experts

Given that: 1 N= 1 kg m `s^(-2)`
1 dyne= 1 g cm `s^(-2)`
But 1 kg= 1000 g and 1 m = 100 cm
`therefore 1 N=1 kg m s^(-2)=(1 kg) (1 m s^(-2))`
`=((1 kg)(1m))/((1s)^(2))=((1000g)(100cm))/((1s)^(2))=10^5gcms^(-2)=10^5` dyne
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Knowledge Check

  • 1 dyne (a unit of force in CGS system) equals to

    A
    `10^(3) g cm//s^(2)`
    B
    `10^(-3) g cm//s^(2)`
    C
    `10^(5) kg cm//s^(2)`
    D
    `10^(-5) kg cm//s^(2)`

  • The unit of force in SI system is newton and it is given as 1 newton = 1 kg m s^(-2) . In CGS system its unit is dyne and it is given as 1 dyne = 1 g cm s^(-2) . Arrange the following steps in a sequential order to relate the SI unit and CGS unit of force: (A) Write the conversions of kg and m, into g and cm, respectively. (B) Substitute the conversions in 1 newton = 1 kg m s^(-2) (C) Write the relation between 1 newton and 1 dyne. (D) Write in place of 1 g cm s^(-2) as 1 dyne.

    A
    A C B D
    B
    A B D C
    C
    BDAC
    D
    CDAB

  • The unit of force in SI system is newton and it is given as 1 newton ="1 kg m s"^(-2) . In CGS system its unit is dyne and it is given as "1 dyne=1 g cm s"^(-2) . Arrange the following steps in a sequential order to relate the SI unit and CGS unit of force. (a) Write the conversions of kg and m, into g and cm, respectively (b) Substitute the conversions in 1 newton = 1 kg m s^2. (c) Write the relation between 1 newton and 1 dyne. (d) Write in place of "1 g cm s"^(-2) as 1 dyne.

    A
    acbd
    B
    abdc
    C
    bdac
    D
    cdab

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    The unit of force in SI system is newton and it is given as 1 newton = 1kg m s^(-2) . In CGS system its unit is dyne and it is given as 1 dyne = 1 g cm s^(2). Arrange the following steps in a sequential order to relate the SI unit and CGS unit of force. (a) Write the conversations of kg and m, into g and cm, respectively. (b) Substitute the conversations in 1 newton = 1 kg m s^(2) Write the relation between 1 newton and dyne. (d) Write in place of 1 g cm s^(-2) as 1 dyne

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