A car moves along a straight path with variable velocity as shown in the figure. When the car is at possiting A, its velocity is `10 m s^(-1)` and when it is at position B, its velocity is `20 m s^(-1)`. If the car takes 5 seconds of time to move from A to B, find the acceleration of the car.

Explanation

Initial position of the car at position `A=u=10ms^(-1)`
Final velocity of the car at position `B=v=20 ms^(-1)`
The change in velocity of the car, `Deltav=v-u=20ms^(-1)-10ms^(-1)`
`=10ms^(-1)`
The time taken for the car to move from A to B, `Deltat=5s`
`:.` Acceleration of the car, `a=(Deltav)/(Deltat)=(10ms^(-1))/(5s)`
`=2ms^(-2)`