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The time period of a simple pendulum is ...

The time period of a simple pendulum is given by `T = 2pi sqrt((l)/(g))`
where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity at that place.
(a) Express 'g' in terms of T
(b) What is the length of the seconds pendulum ? (Take `g = 10 m s^(-2)`)

Text Solution

Verified by Experts

`T= 2pi sqrt((l)/(g))`
Square equation (1) on both the sides write g in term of .l. and "T.
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Knowledge Check

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    D
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