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The total surface area of a cuboidal box...

The total surface area of a cuboidal box is given by: `A=2(lb+bh+lh)`. The follwing are the steps involved in marketing b as the subject of the formula.Arrange them in sequential order.
(A) `(A)/(2)-lh=lb+bh`
(B) `A=2(lb+bh+lh) implies (A)/(2)=lb+bh+lh`
(C) `b=(A-2lh)/(1(l+h))`
(D) `b(l+h)=(A-2lh)/(2)`

A

BDAC

B

DBAC

C

BCAD

D

BADC

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The total surface area of a cuboid is S = 2(lb+ bh +lh). Make l as the subject of the formula.

    A
    ` l = (S)/(2(b+h))`
    B
    ` l = (S)/(b+h) +(bh)/(b+h)`
    C
    ` l = (S-2bh)/(2(b+h))`
    D
    ` l = ( S-bh)/(b+h)`

  • The total surface area of a cuboid is S=2(lb+bh+lh) . Make l as the subject of the formula.

    A
    `l=(S)/(2(b+h))`
    B
    `l=(S)/(b+h)+(bh)/(b+h)`
    C
    `l=(2-2bh)/(2(b+h))`
    D
    `l=(S-bh)/(b+h)`

  • Make l as the subject of the formula A=2(lb+bh+hl). The following steps are involved in solving the above problem Arrange them in sequential order.

    A
    `lb+bh+hl=(A)/(2)`
    B
    `l=(A-2bh)/(2(b+h))`
    C
    `2(lb+bh+hl)=A`
    D
    `l(b+h)=(A)/(2)-bh`

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