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The mass of copper that will be deposite...

The mass of copper that will be deposited at cathode in electrolysis of 0.2 M solution of copper sulphate when a quantity of electricity equal to that required to liberate 2.24 L of hydrogen from 0.1 M aqueous `H_2SO_4` is passed will be (At. mass of Cu = 63.5)

A

1.59 g

B

3.18 g

C

6.35 g

D

12.70 g

Text Solution

Verified by Experts

The correct Answer is:
C
Applying, Faraday.s second law
`w_(Cu)/w_(H_2)=E_(Cu)/E_(H_2)`
22.4 L of `H_2` gas weight =2 g
`therefore` 2.24 L of `H_2` will weigh = `2/22.4xx2.24=0.2` g
`w_(Cu)=31.75/1xx0.2=6.35` g
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Knowledge Check

  • The mass of copper that will be deposited at cathode in electrolysis of 0.2M solution of copper sulphate when a quantity of electricity equal to that required to liberate 2.24L of hydrogen from 0.1M aqueous H_(2)SO_(4) is passed ( atomic mass of Cu=63.5) will be

    A
    `1.59g`
    B
    `3.18g`
    C
    `6.35g`
    D
    `12.70g`

  • To deposits 0.634 g of copp·er by electrolysis of aqueous cupric sulphate solution the amount of electricity required (in coulombs) 0 is

    A
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    B
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    3960
    D
    1930

  • To deposit 0.6354 g of copper by electrolysis of aqueous cupric sulphate solution, the amount of electricity required (in Coulombs) is

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    9650
    B
    4825
    C
    3860
    D
    1930

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