Home
Class 12
CHEMISTRY
The plot of log k vs 1/T helps to calcul...

The plot of log k vs 1/T helps to calculate

A

energy of activation

B

rate constant of the reaction

C

order of the reaction

D

energy of activation as well as the frequency factor.

Text Solution

Verified by Experts

The correct Answer is:
D

Plot of log k vs 1`//`T helps to calculate `E_a` and A.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL KINETICS

    MTG GUIDE|Exercise CHECK YOUR NEET VITALS|25 Videos
  • CHEMICAL KINETICS

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|22 Videos
  • CHEMICAL KINETICS

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|22 Videos
  • BIOMOLECULES

    MTG GUIDE|Exercise AIPMT/NEET (MCQS)|19 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    MTG GUIDE|Exercise AIPMT/NEET |9 Videos

Similar Questions

Explore conceptually related problems

The plots of log_(10) K vs. 1//T leads toa straight line having intercept equal to:

For the reaction aA+bBrarrcC+dD , the plot of log k vs 1/T is given below, The temperature at which the rate constant of the reaction is 10^(-4) s^(-1) is _____K. (Rouded -off the nerest integer) [Given : The rate constant of the reaction is 10^(-5) s^(-1) at 500 K.]

Knowledge Check

  • The plot og log k vs 1//T helps to calculate

    A
    The energy of activation
    B
    The rate constant of the reaction
    C
    The order of the reaction
    D
    The energy of activations as well as the frequency factor
  • A graph plotted between log K vs 1//T for calculating activation energy is shown by

    A
    B
    C
    D
  • For a first order reaction, the plot of log k against 1/T is a straight line. The slope of the line is equal to

    A
    `(E_(a))/(R)`
    B
    `(2.303)/(E_(a)xxR)`
    C
    `(E_(a))/(2.303)`
    D
    `(-E_(a))/(2.303 R)`
  • Similar Questions

    Explore conceptually related problems

    When a plot of log k versus 1//T of chemical reaction is made, the energy of activation is given by the slope of straight line

    A graph plotted between log k versus 1/T for calculating activation energy is shown by

    Which of the plots of ln K vs (1/T) is/are correct?

    A graph plotted between log k versus 1//T for calculating activation energy is shown by

    In accordance to Arrhenius equation, the plot of log k against (1)/(T) is a straight line. The slope of the line is equal to