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Electric current is passed through two c...

Electric current is passed through two cells A and B in series. Cell A contains aqueous solution of `Ag_(2) SO_(4)` and platinum electrodes. Cell B contains aqueous solution of `CuSO_(4)` and copper electrodes. The current is passed till 1.6g of oxygen is liberated at the anode in cell A. Calculate the quantities of copper and silver deposited at the cathode of the two cells.
[ Atomic mass, O = 16, Cu 63.5, Ag = 108]

Text Solution

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The correct Answer is:
Ag = 21.6g, Cu = 6.35g
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When a current of 0.75 ampere is passed through CuSO_4 for 25 mins, 0.369 g of copper is deposited at the cathode. Calculate the atomic mass of copper.

An electroytic cell contains a solution of Ag_2SO_4 and platinum electrodes. A current is passeduntil 1.6 g of O-2 has been liberated at anode. The amount of Ag deposited at cathode would be :

Knowledge Check

  • An electrolytic cell contains a solution of Ag_(2)SO_(4) and Platinum electrodes a current is passed until 1.6 gm of O_(2) has been liberated at anode.The amount of Ag deposited at cathode would be

    A
    1.6g
    B
    6.5g
    C
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    D
    3.2g

  • An electrolytec cell contains a solution of AgNO_3 and have platinum electrodes. A current is passed untill 1.6 g of O_2 has been liberated at anode. The amount of silver peposited at cathode would be :

    A
    `107.88`g
    B
    `1.6`g
    C
    `0.8`g
    D
    `21.60 g`

  • An electrolytec cell contains a solution of AgNO_3 and have platinum electrodes. A current is passed untill 1.6 g of O_2 has been liberated at anode. The amount of silver peposited at cathode would be :

    A
    `107.88`g
    B
    `1.6`g
    C
    `0.8`g
    D
    `21.60 g`

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