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From the following molar conductivities ...

From the following molar conductivities at infinite dilution.
`Lambda_(m)^(@) ` for `Ba(OH)_(2) = 457.6 Omega^(-1) cm^(2) "mol"^(-1)`
`Lambda_(m)^(@) ` for `BaCl_(2) = 240.6 Omega^(-1) cm^(2) "mol"^(-1)`
`Lambda_(m)^(@) ` for `NH_(4) Cl = 129.8 Omega^(-1) cm^(2) "mol"^(-1)`
Calculate `Lambda_(m)^(@)` for `NH_(4) OH`.

Text Solution

Verified by Experts

The correct Answer is:
238.3 `s^(-1) cm^(2)"mol"^(-1)`
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The values of Lambda_m^@ for NH_4Cl , NaOH and NaCl are 120.6, 248.2 and 136.4 ohm^-1 cm^2 mol^-1 respectively. Calculate Lambda_m^@ for NH_4OH .

Calculate the value of Molar conductivity of MgCl_(2) at infinite dilution if lamda_(Mg^2+)=107.12 ohm^(-1)cm^2 mol^(-1) and lambda_(Cl^-1)= 76.34 ohm^(-1)cm^2 mol^(-1)

Knowledge Check

  • The value of Lambda_(eq) ^(oo) for NH_(4) Cl NaOH and NaCl are respectively, 149.74, 248.1 and 126.4 Omega^(-1) cm^(2) "equiv"^(-1) . The value of Lambda_(eq)^(oo) of NH_(4) OH is

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    B
    271.44
    C
    71.44
    D
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