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Two insulated charged copper spheres A a...

Two insulated charged copper spheres A and.B of identical size have charges `q_A ` and `q_B ` respectively. A third sphere C of the same size but uncharged is brought in contact with the first and then in contact with the second and finally removed from both. What are the new charges on A and B?

Text Solution

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When sphere C is brought in contact with A, then charge on sphere C, `q_C = (q_A+0)/(2) = (q_A)/(2)`
and new charge on sphere ` A, q_A= (q_A)/(2)`
When sphere C is brought in contact with B. charge on sphere C,
` " " q_C = (q_C + q_B)/(2)`
` = ((q_A)/(2) +q_B)/(2)`
` = (q_A + 2q_B)/(4)`
`therefore ` New charge on sphere B,
` q_B. = (q_A +2q_B)/(4)`
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Knowledge Check

  • Two conducting spheres of same radius r are having charges q_1 and q_2 the ratio of their intensities is :

    A
    `E_1/E_2=q_1/q_2`
    B
    `E_1/E_2=q_1^2/q_2^2`
    C
    `E_1/E_2`
    D
    `E_1/E_2=q_1sqrtq_2`

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