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The shape of ClO(3)^(-) ion according to...

The shape of `ClO_(3)^(-)` ion according to VSEPR theory is:

A

Triangle planar

B

Pyramidal

C

Tetrahedral

D

square planar.

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To determine the shape of the \( \text{ClO}_3^{-} \) ion according to VSEPR theory, we can follow these steps: ### Step 1: Determine the Valence Electrons Chlorine (Cl) is in Group 17 of the periodic table, which means it has 7 valence electrons. Each oxygen (O) atom has 6 valence electrons. Since there are three oxygen atoms, the total number of valence electrons contributed by oxygen is \( 3 \times 6 = 18 \). Additionally, the \( \text{ClO}_3^{-} \) ion has an extra electron due to its negative charge. Calculating the total number of valence electrons: \[ \text{Total valence electrons} = 7 (\text{from Cl}) + 18 (\text{from 3 O}) + 1 (\text{extra electron}) = 26 \] ### Step 2: Draw the Lewis Structure In the Lewis structure of \( \text{ClO}_3^{-} \): - Chlorine will be the central atom. - It will form one single bond with one oxygen atom and two double bonds with the other two oxygen atoms. - Chlorine will have one lone pair of electrons. The structure can be represented as follows: - One Cl-O single bond - Two Cl=O double bonds - One lone pair on the chlorine atom ### Step 3: Determine the Steric Number The steric number is calculated by adding the number of bonded atoms and lone pairs around the central atom (Cl): - There are 3 bonded oxygen atoms (1 single bond + 2 double bonds). - There is 1 lone pair of electrons on chlorine. Thus, the steric number is: \[ \text{Steric Number} = 3 (\text{bonded atoms}) + 1 (\text{lone pair}) = 4 \] ### Step 4: Predict the Shape Using VSEPR Theory According to VSEPR theory, a steric number of 4 corresponds to a tetrahedral electron pair geometry. However, since there is one lone pair, the molecular geometry will be different. The presence of the lone pair will repel the bonded pairs, resulting in a trigonal pyramidal shape for the \( \text{ClO}_3^{-} \) ion. ### Conclusion The shape of the \( \text{ClO}_3^{-} \) ion according to VSEPR theory is **trigonal pyramidal**. ---

To determine the shape of the \( \text{ClO}_3^{-} \) ion according to VSEPR theory, we can follow these steps: ### Step 1: Determine the Valence Electrons Chlorine (Cl) is in Group 17 of the periodic table, which means it has 7 valence electrons. Each oxygen (O) atom has 6 valence electrons. Since there are three oxygen atoms, the total number of valence electrons contributed by oxygen is \( 3 \times 6 = 18 \). Additionally, the \( \text{ClO}_3^{-} \) ion has an extra electron due to its negative charge. Calculating the total number of valence electrons: ...
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  • The shape of CIF_(3) according to VSEPR model is

    A
    planar triangle
    B
    T-shape
    C
    tetrahedral
    D
    square planar
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