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L.C.A.O. Principle is involved in the fo...

L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order `(B.O.)=1/2(N_(b)-N_(a))` helps in predicting formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well.
In the formation of `N_(2)^(+)` from `N_(2),` the electron is removed from a

A

`sigma`orbital

B

`pi`orbital

C

`sigma**`-orbital

D

`pi**`-prbital.

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To solve the question regarding the formation of \( N_2^+ \) from \( N_2 \) and the removal of an electron, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Molecular Orbital Theory**: - According to the Molecular Orbital (MO) theory, atomic orbitals combine to form molecular orbitals. These molecular orbitals can be bonding or antibonding. - The bonding molecular orbitals have lower energy than the atomic orbitals from which they are formed, while antibonding molecular orbitals have higher energy. 2. **Determine the Electron Configuration of \( N_2 \)**: - The nitrogen atom has an atomic number of 7, hence \( N_2 \) has a total of 14 electrons (7 from each nitrogen atom). - The molecular orbital configuration for \( N_2 \) is: \[ \sigma_{1s}^2 \sigma^*_{1s}^2 \sigma_{2s}^2 \sigma^*_{2s}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \sigma_{2p_z}^2 \] - This configuration shows that the bonding orbitals are filled before the antibonding orbitals. 3. **Identify the Highest Occupied Molecular Orbital (HOMO)**: - The highest occupied molecular orbital in \( N_2 \) is \( \sigma_{2p_z} \), which contains 2 electrons. 4. **Remove an Electron to Form \( N_2^+ \)**: - To form \( N_2^+ \), we need to remove one electron from the \( N_2 \) molecule. - The electron will be removed from the HOMO, which is \( \sigma_{2p_z} \). 5. **Write the Molecular Orbital Configuration for \( N_2^+ \)**: - After removing one electron from \( N_2 \), the configuration for \( N_2^+ \) will be: \[ \sigma_{1s}^2 \sigma^*_{1s}^2 \sigma_{2s}^2 \sigma^*_{2s}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \sigma_{2p_z}^1 \] - This indicates that \( N_2^+ \) has one unpaired electron in the \( \sigma_{2p_z} \) orbital. 6. **Conclusion**: - The electron is removed from the \( \sigma_{2p_z} \) molecular orbital to form \( N_2^+ \).

To solve the question regarding the formation of \( N_2^+ \) from \( N_2 \) and the removal of an electron, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Molecular Orbital Theory**: - According to the Molecular Orbital (MO) theory, atomic orbitals combine to form molecular orbitals. These molecular orbitals can be bonding or antibonding. - The bonding molecular orbitals have lower energy than the atomic orbitals from which they are formed, while antibonding molecular orbitals have higher energy. ...
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L.C.A.O. Principle is involved in the formationof the molecular orbitals according ot molecular orbital theory. The energy of the bonding molecular orbital is less than that of thecombining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting (i) formation of molecules/molecular ions, bond dossociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic prbitals at the time of overlap must have the same symmetry as well. Bond arder is :

L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting (i) formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. The bond order (B.O.) in B_(2) molecule is:

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