Statement 1: `SF_(6)` molecular has octahedral geometry
Statement 2: Sulphur atom in `SF_(6)` molecule is in `sp^(3)d` hybridisation state.

Options

A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-1
B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-1
C. Statement-1 is true, Statement-2 is false.
D. Statement-1 is false, Statement-2 is true.

Explanation

To analyze the statements regarding the molecule SF₆ (sulfur hexafluoride), we will evaluate each statement step by step.

### Step 1: Analyze Statement 1
**Statement 1**: SF₆ molecule has octahedral geometry.

- **Explanation**:
- SF₆ consists of one sulfur atom and six fluorine atoms.
- Sulfur has six valence electrons, and in SF₆, all six of these electrons are used to form bonds with six fluorine atoms.
- Since there are no lone pairs on the sulfur atom and it is surrounded by six bonding pairs, the molecular geometry adopts an octahedral shape.

- **Conclusion**: Statement 1 is **True**.

### Step 2: Analyze Statement 2
**Statement 2**: Sulfur atom in SF₆ molecule is in sp³d hybridization state.

- **Explanation**:
- To determine the hybridization of the sulfur atom, we look at the number of bonding pairs and lone pairs.
- In SF₆, there are six bonding pairs and no lone pairs.
- The hybridization can be determined using the formula:
- For 6 bonding pairs, the hybridization is sp³d² (not sp³d).
- Therefore, the correct hybridization for sulfur in SF₆ is sp³d².

- **Conclusion**: Statement 2 is **False**.

### Final Conclusion
- Statement 1 is True.
- Statement 2 is False.