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The number of carbon atoms per unit cell...

The number of carbon atoms per unit cell of diamond unit cell is

A

1

B

4

C

8

D

12

Text Solution

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The correct Answer is:
To determine the number of carbon atoms per unit cell in a diamond unit cell, we can follow these steps: ### Step 1: Understand the Structure of Diamond Diamond has a face-centered cubic (FCC) structure with additional carbon atoms located in the tetrahedral voids. ### Step 2: Count the Atoms at the Corners In a cubic unit cell, there are 8 corners. Each corner atom contributes \( \frac{1}{8} \) of its volume to the unit cell. Therefore, the contribution from the corner atoms is: \[ \text{Contribution from corners} = 8 \times \frac{1}{8} = 1 \text{ atom} \] ### Step 3: Count the Atoms at the Face Centers In the diamond structure, there are 6 face centers, and each face-centered atom contributes \( \frac{1}{2} \) of its volume to the unit cell. Thus, the contribution from the face-centered atoms is: \[ \text{Contribution from face centers} = 6 \times \frac{1}{2} = 3 \text{ atoms} \] ### Step 4: Count the Atoms in the Tetrahedral Voids In the diamond structure, there are 8 tetrahedral voids in the FCC unit cell, but only half of them (4) are occupied by carbon atoms in the diamond structure. Each of these contributes 1 atom: \[ \text{Contribution from tetrahedral voids} = 4 \text{ atoms} \] ### Step 5: Calculate the Total Number of Carbon Atoms Now, we can add the contributions from all the sources: \[ \text{Total number of carbon atoms} = \text{Contribution from corners} + \text{Contribution from face centers} + \text{Contribution from tetrahedral voids} \] \[ \text{Total number of carbon atoms} = 1 + 3 + 4 = 8 \text{ atoms} \] ### Conclusion The number of carbon atoms per unit cell of diamond is **8**.

To determine the number of carbon atoms per unit cell in a diamond unit cell, we can follow these steps: ### Step 1: Understand the Structure of Diamond Diamond has a face-centered cubic (FCC) structure with additional carbon atoms located in the tetrahedral voids. ### Step 2: Count the Atoms at the Corners In a cubic unit cell, there are 8 corners. Each corner atom contributes \( \frac{1}{8} \) of its volume to the unit cell. Therefore, the contribution from the corner atoms is: \[ ...
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