To determine the electronic configuration of Palladium (Pd) with atomic number 46, we will follow the steps below:
### Step-by-Step Solution:
1. **Identify the Atomic Number**:
- The atomic number of Palladium (Pd) is 46. This means that a neutral atom of Palladium has 46 electrons.
2. **Understand the Order of Filling Orbitals**:
- Electrons fill atomic orbitals in a specific order based on the Aufbau principle, which states that electrons occupy the lowest energy orbitals first. The order of filling is as follows:
- 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.
3. **Fill the Orbitals**:
- We will fill the orbitals according to the order mentioned above until we reach 46 electrons:
- 1s² (2 electrons)
- 2s² (2 electrons)
- 2p⁶ (6 electrons)
- 3s² (2 electrons)
- 3p⁶ (6 electrons)
- 4s² (2 electrons)
- 3d¹⁰ (10 electrons)
- 4p⁶ (6 electrons)
- 5s² (2 electrons)
- 4d¹⁰ (10 electrons)
4. **Count the Electrons**:
- Now, let's count the total number of electrons filled:
- 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 = 46 electrons.
5. **Write the Electronic Configuration**:
- The electronic configuration for Palladium (Pd) can be written as:
- **[Kr] 4d¹⁰ 5s²**
- Here, [Kr] represents the noble gas core configuration of Krypton, which accounts for the first 36 electrons.
### Final Answer:
The electronic configuration of Palladium (Pd) is **[Kr] 4d¹⁰ 5s²**.
