Home
Class 11
CHEMISTRY
Ne, Na^(+) and F^(-) have the same...

Ne, `Na^(+)` and `F^(-)` have the same

A

mass number

B

number of nucleons

C

number electrons

D

number of protons

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding Ne, Na⁺, and F⁻ having the same properties, we will analyze each species in terms of their atomic structure, specifically focusing on the number of electrons, protons, and nucleons. ### Step-by-Step Solution: 1. **Identify the Atomic Number and Electron Count of Neon (Ne)**: - Neon (Ne) has an atomic number of 10. - This means it has 10 protons and, in a neutral atom, also 10 electrons. 2. **Identify the Atomic Number and Electron Count of Sodium Ion (Na⁺)**: - Sodium (Na) has an atomic number of 11. - A Na⁺ ion indicates that it has lost one electron. Therefore, the number of electrons in Na⁺ is: \[ 11 \text{ (atomic number)} - 1 \text{ (lost electron)} = 10 \text{ electrons} \] - The number of protons remains 11. 3. **Identify the Atomic Number and Electron Count of Fluoride Ion (F⁻)**: - Fluorine (F) has an atomic number of 9. - A F⁻ ion indicates that it has gained one electron. Therefore, the number of electrons in F⁻ is: \[ 9 \text{ (atomic number)} + 1 \text{ (gained electron)} = 10 \text{ electrons} \] - The number of protons remains 9. 4. **Compare the Number of Electrons**: - Ne: 10 electrons - Na⁺: 10 electrons - F⁻: 10 electrons - All three species have the same number of electrons, which is 10. 5. **Determine the Mass Number (Number of Nucleons)**: - The mass number is the sum of protons and neutrons. - For Ne (atomic number 10), the most common isotope has 10 neutrons, so: \[ \text{Mass number of Ne} = 10 \text{ protons} + 10 \text{ neutrons} = 20 \] - For Na⁺ (atomic number 11), the most common isotope has 12 neutrons, so: \[ \text{Mass number of Na⁺} = 11 \text{ protons} + 12 \text{ neutrons} = 23 \] - For F⁻ (atomic number 9), the most common isotope has 10 neutrons, so: \[ \text{Mass number of F⁻} = 9 \text{ protons} + 10 \text{ neutrons} = 19 \] 6. **Conclusion**: - While Ne, Na⁺, and F⁻ have the same number of electrons (10), they do not have the same mass number or number of protons. - Therefore, the correct answer is that Ne, Na⁺, and F⁻ are isoelectronic species, having the same number of electrons.

To solve the question regarding Ne, Na⁺, and F⁻ having the same properties, we will analyze each species in terms of their atomic structure, specifically focusing on the number of electrons, protons, and nucleons. ### Step-by-Step Solution: 1. **Identify the Atomic Number and Electron Count of Neon (Ne)**: - Neon (Ne) has an atomic number of 10. - This means it has 10 protons and, in a neutral atom, also 10 electrons. ...
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The ionic radii of O^(2-),F^(-) , Na^(+) and Mg^(2+) are in the order :

Out of N, O, Ne, Na, Na^(+) select the species which have maximum and minmum ionization energy.

The Ne atom has 10 times the mass of H_(2) molecule. Which of the following statements is true? I. At 25^(@)C both of them have the same kinetic energy. II. Ten moles of H_(2) would have the same volume as 1 mole of Ne at same temp. and pressure. III. One mole of Ne exerts the same pressure as one mole of H_(2) at STP. IV. A H_(2) molecule travels 10 times faster than Ne atom at same temperature. V. At STP, one litre of Ne has 10 times the density of 1 litre of H_(2).

Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is

Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is

Observe the following statements regarding isotones : a. .^(39)K and .^(40)Ca are isotones. b. Nucleides having different atomic number (Z) and mass numbers (a) but same number of neutrons (n) are called isotones. c. .^(19)F and .^(23)Na are isotones. The correct answer is -

Is it possible for Ne_(2) and F_(2)^(-) to exist?

Largest in size out of Na^(+),Ne and F^(-) is:

Largest in size out of Na^(+),Ne and F^(-) is:

The size of isoelectronic species O^(-2) F^(-) and Na^(+) is affected by: