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The value of gas constant R is 8.314 X. ...

The value of gas constant R is 8.314 X. Here X represents

A

Litre atm. `K^(-1) mol^(-1)`

B

Cal `mol^(-1) K^(-1)`

C

`JK^(-1) mol^(_1)`

D

None of the above

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The correct Answer is:
To determine the value of gas constant R, which is given as 8.314 X, we need to identify what X represents in terms of units. ### Step-by-Step Solution: 1. **Understand the Ideal Gas Law**: The ideal gas equation is given by: \[ PV = nRT \] where: - \( P \) = pressure - \( V \) = volume - \( n \) = number of moles - \( R \) = universal gas constant - \( T \) = temperature 2. **Rearranging the Ideal Gas Law**: We can rearrange this equation to solve for R: \[ R = \frac{PV}{nT} \] 3. **Substituting Standard Conditions**: At standard conditions, we can use: - \( P = 1 \, \text{atm} \) - \( V = 22.4 \, \text{L} \) - \( n = 1 \, \text{mol} \) - \( T = 273 \, \text{K} \) Substituting these values into the equation for R: \[ R = \frac{(1 \, \text{atm})(22.4 \, \text{L})}{(1 \, \text{mol})(273 \, \text{K})} \] 4. **Calculating R**: Performing the calculation: \[ R = \frac{22.4}{273} \approx 0.0821 \, \text{L atm K}^{-1} \text{mol}^{-1} \] However, we need the value in joules. 5. **Converting to Joules**: We know that: \[ 1 \, \text{atm} \cdot \text{L} = 101.325 \, \text{J} \] Therefore: \[ R = 0.0821 \, \text{L atm K}^{-1} \text{mol}^{-1} \times 101.325 \, \text{J/L atm} \approx 8.314 \, \text{J K}^{-1} \text{mol}^{-1} \] 6. **Identifying X**: From our calculation, we find that: \[ R = 8.314 \, \text{J K}^{-1} \text{mol}^{-1} \] Thus, \( X \) represents the unit "J K\(^{-1}\) mol\(^{-1}\)". ### Conclusion: The value of gas constant R is 8.314 X, where X represents "J K\(^{-1}\) mol\(^{-1}\)".

To determine the value of gas constant R, which is given as 8.314 X, we need to identify what X represents in terms of units. ### Step-by-Step Solution: 1. **Understand the Ideal Gas Law**: The ideal gas equation is given by: \[ PV = nRT ...
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