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-273.15C is...

`-273.15C` is

A

`-0.15^(@)C`

B

`0 K`

C

`-0.15^(@)F`

D

`0^(@)F`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the temperature of -273.15°C, we need to convert it into Kelvin and Fahrenheit to find the correct answer. ### Step-by-Step Solution: 1. **Understanding the Temperature Scale**: - The question provides a temperature in Celsius (-273.15°C) and asks for its equivalent in Kelvin and Fahrenheit. 2. **Convert Celsius to Kelvin**: - The formula to convert Celsius to Kelvin is: \[ K = C + 273.15 \] - Substituting the given Celsius value: \[ K = -273.15 + 273.15 = 0 \text{ K} \] 3. **Convert Celsius to Fahrenheit**: - The formula to convert Celsius to Fahrenheit is: \[ F = \left(C \times \frac{9}{5}\right) + 32 \] - Substituting the given Celsius value: \[ F = \left(-273.15 \times \frac{9}{5}\right) + 32 \] - Calculating: \[ F = \left(-491.67\right) + 32 = -459.67 \text{ °F} \] 4. **Identifying the Correct Option**: - The converted values are: - 0 Kelvin - -459.67 Fahrenheit - From the options provided: - Option A: -1.5 °C (Incorrect) - Option B: 0 Kelvin (Correct) - Option C: -0.15 °F (Incorrect) - Option D: 0 °F (Incorrect) Thus, the correct answer is **Option B: 0 Kelvin**.
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Temperature cannot be expressed below -273.15^@C . This led to the need of Kelvin scale.

The behaviour of ideal gas is goverened by various gas laws which are described by mathematical statements as given below: ( i ) PV=k (constant) at constant n and T ( ii ) V//T=k_(2) (constant) at constant n and P ( iii ) V//n=k_(3) (constant) at constant T and P ( iv ) PV=nRT ( v ) P//T=k_(4) (constant) at constant n and V Answer the following If we plot a graph between volume ( L ) and temperature ( -273.15^(@)C ) by studying their variation for 2.0 g of certain ideal gas at 1 bar pressure, the graph obtained is a straight line which is

Knowledge Check

  • Assertion : The lowest hypothetical or imaginary temperature at which gases are supposed to occupy zero volume is called absolute zero . Reason : Volume of the gas at -273 . 15 C^(@) becomes zero i.e. gas does not exist at this temperature .

    A
    If both assertion and reason are true and reason is the correct explanation of assertion .
    B
    If both assertion and reason are true but reason is not the correct explanation of assertion .
    C
    If assertion is true but reason is false .
    D
    If both assertion and reason are false .
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