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In an equilateral triangle, the inradius...

In an equilateral triangle, the inradius, circumradius, and one of the exradii are in the ratio

A

2:4:5

B

1:2:3

C

1:2:4

D

2:4:3

Text Solution

Verified by Experts

Let `a` is the side of the equilateral triangle.
Then, `Delta = sqrt3/4a^2`
`s = (a+a+a)/2 = (3a)/2`
Now, Inradius `(r) = Delta/s = (sqrt3/4a^2)/((3a)/2) = a/(2sqrt3)`
Circumradius`(R) = (abc)/(4Delta) = (a^3)/(sqrt3/a^2) = a/sqrt3`
Exradii `(r_1) = Delta/(s-a) = (sqrt3/4a^2)/(a/2) = sqrt3/2a`
`:. r:R:r_1 = a/(2sqrt3):a/sqrt3:(sqrt3a)/2 = 1:2:3`
So, option `(b)` is the correct option.
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