Home
Class 11
MATHS
Tangents are drawn to x^2+y^2=1 from any...

Tangents are drawn to `x^2+y^2=1` from any arbitrary point `P` on the line `2x+y-4=0` . The corresponding chord of contact passes through a fixed point whose coordinates are
(a) `(1/2,1/2)` (b) `(1/2,1)`(c) `(1/2,1/4)` (d) `(1,1/2)`

Answer

Step by step text solution for Tangents are drawn to x^2+y^2=1 from any arbitrary point P on the line 2x+y-4=0 . The corresponding chord of contact passes through a fixed point whose coordinates are (a) (1/2,1/2) (b) (1/2,1)(c) (1/2,1/4) (d) (1,1/2) by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    CENGAGE PUBLICATION|Exercise All Questions|877 Videos

  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE PUBLICATION|Exercise Multiple correct answers type|11 Videos

Similar Questions

Explore conceptually related problems

Tangents are drawn from the points on the line x−y−5=0 to x^2+4y^2=4 , then all the chords of contact pass through a fixed point, whose coordinate are

From a variable point p on line 2x−y-1=0 pair of tangents are drawn to parabola x^2=8y then chord of contact passes through a fixed point.

If a , b and c are in A P , then the straight line a x+b y+c=0 will always pass through a fixed point whose coordinates are (a) (1,2) (b) (1,-2) (c) (2,3) (d) (0,0)

If tangents are drawn to y^2=4a x from any point P on the parabola y^2=a(x+b), then show that the normals drawn at their point for contact meet on a fixed line.

The chords of contact of the pair of tangents drawn from each point on the line 2x + y=4 to the circle x^2 + y^2=1 pass through the point (h,k) then 4(h+k) is

The common chord of the circle x^2+y^2+6x+8y-7=0 and a circle passing through the origin and touching the line y=x always passes through the point. (a) (-1/2,1/2) (b) (1, 1) (c) (1/2,1/2) (d) none of these

y=x+2 is any tangent to the parabola y^2=8xdot The point P on this tangent is such that the other tangent from it which is perpendicular to it is (a) (2,4) (b) (-2,0) (c) (-1,1) (d) (2,0)

y=x is tangent to the parabola y=2ax^(2)+c . If (1,1) is the point of contact, then a is

If a/sqrt(b c)-2=sqrt(b/c)+sqrt(c/b), where a , b , c >0, then the family of lines sqrt(a)x+sqrt(b)y+sqrt(c)=0 passes though the fixed point given by (a) (1,1) (b) (1,-2) (c) (-1,2) (d) (-1,1)

Tangent are drawn from the point (-1,2) on the parabola y^2=4x . Find the length that these tangents will intercept on the line x=2.

Home
Profile