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Arrange (log)2 5,(log)(0. 5)5,(log)7 5,(...

Arrange `(log)_2 5,(log)_(0. 5)5,(log)_7 5,(log)_3 5` in decreasing order.

Text Solution

Verified by Experts

` log_(2) 5 ` = exponent of 2 for which we get 5
` log_(7) 5 ` = exponent of 7 for which we get 5
Clearly, ` log_(2) 5 gt log_(7) 5`
With similar reasons, we have ` log_(2) 5 gt log_(3) 5 gt log_(7) 5`.
Also ` log_(0.5) 5 lt 0`
`:. log_(2) 5 gt log_(3) 5 gt log_(7) 5 gt log_(0.5) 5`
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