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If A, B are square materices of same ord...

If A, B are square materices of same order and B is a skewsymmetric matrix, show that `A^(T)BA` is skew-symmetric.

Text Solution

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Matric B is skew-symmetric
`:. B^(T)=-B`
Now, `(A^(T)BA)^(T)=A^(T)B^(T) (A^(T))^(T)" "("as "(AB)^(T)=B^(T)A^(T))`
`=A^(T)(-B)A`
`=-A^(T) BA`
Hence, `A^(T)BA` is a skew-symmetric matrix.
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Knowledge Check

  • If A and B are two square matrices of the same order, then (A-B)^(2) is equal to -

    A
    `A^(2)-2AB+B^(2)`
    B
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  • If A and B are square matrices of the same order such that AB = A and BA = B, then……

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    `A^(2)=A`
    B
    `B^(2)=B`
    C
    `A=I`
    D
    `B=I`
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