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The eccentricity of the conjugate hyperb...

The eccentricity of the conjugate hyperbola of the hyperbola `x^2-3y^2=1` is (a) 2 (b) `2sqrt(3)` (c) 4 (d) `4/5`

A

2

B

`2//sqrt3`

C

4

D

`4//5`

Text Solution

Verified by Experts

The correct Answer is:
A
The given hyperbola is
`(x^(2))/(1)-(y^(2))/(1//3)=1`
Its eccentricity e is given by
`(1)/(3)=1(e^(2)-1)`
Hence, eccentricity e' of the hyperbola is given by
`1=(1)/(3)(e'^(2)-1)`
`"or "e'^(2)=4`
`"or "e'=2`
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