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One ticket is selected at ransom form 50...

One ticket is selected at ransom form 50 tickets numbered `00,01,02,…,49.` Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, is

A

`1/14`

B

`1/7`

C

`5/14`

D

`1/50`

Text Solution

Verified by Experts

The correct Answer is:
A

`S={00,01,02,....,49}`
Let A be the event that the sum of the digits on the selected ticket is 8. Then
`A={08,17,26,35,44}`
Let B be the event that the product of the digits is zero. Than
`B={00,01,02,03,...,09,10,20,30,40}`
`thereforeAnnB={8}`
The required probability is
`P(A//B)=(P(AnnB))/(P(B))`
`=(1/50)/(14/50)=1/14`
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