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If y=x+2 is normal to the parabola y^2=4...

If `y=x+2` is normal to the parabola `y^2=4a x ,` then find the value of `adot`

Text Solution

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Normal to the parabola `y^(2)=4ax` having slope m is `y-mx-2am-am^(3)`
The given normal is y=x+2. Therefore,
`m=1 and -2am-am^(3)=2`
`or-2a(1)-a(1)^(3)=2`
`ora=-(2)/(3)`
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