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How many normals can be drawn to parabol...

How many normals can be drawn to parabola `y^(2)=4x` from point (15, 12)? Find their equation. Also, find corresponding feet of normals on the parabola.

Text Solution

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Equation of the normal to parabola `y^(2)=4x` having slope m is
`y=mx-2m-m^(3)`
If it passes through the point (15, 12), then
`12=15m-2m-m^(3)`
`or" "m^(2)-13m+12=0`
Clearly, one root of the equation is 1.
`:." "(m-1)(m^(2)+m-12)=0`
`rArr" "(m-1)(m-3)(m+4)=0`
`rArr" "m=1,3,-4`
Thus, three normal can be drawn from (15, 12).
The equations of normal and corresponding points on the curve are given by
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Knowledge Check

  • The equation of the normal to the parabola y^(2) =4ax at the point (at^(2), 2at) is-

    A
    ` tx+y=2at+at^(3)`
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    ` x+ty=2at+at^(3)`
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  • The normal to the parabola y^(2)=8x at the point (2, 4) meets the parabola again at the point-

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    `(-18, -12)`
    B
    `(-18, 12)`
    C
    `(18, 12)`
    D
    `(18, -12)`
  • If three normals are drawn from the point (c, 0) to the parabola y^(2)= x , then-

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    ` c lt (1)/(2) `
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    ` c ge 2 `
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