Consider two functions
`f(x)={([x]",",-2le x le -1),(|x|+1",",-1 lt x le 2):} and g(x)={([x]",",-pi le x lt 0),(sinx",",0le x le pi):}`
where [.] denotes the greatest integer function.
The number of integral points in the range of `g(f(x))` is

Options

A. 2
B. 4
C. 3
D. 5

Answer

B

Explanation

`g(f(x))={([f(x)]",",-pi le f(x) lt 0),(sin f(x)",",0 le f(x) le pi):}`
`={([[x]]",",-pi le [x] lt 0",",-2 le x le -1),([|x|+1]",",-pi le |x| +1 lt 0",",-1 lt x le 2),(sin[x]",",0 le [x] le pi",",-2 le x le -1),(sin(|x|+1)",",0le |x|+1 le pi",",-1 lt x le 2):}`
`={([x]",",-2 le x le -1),(sin(|x|+1)",", -1 lt x le 2):}`
Hence, the domain is [-2, 2].
Also, for `-2 le x le -1, [x]= -2, -1,`
and for `-1 lt x le 2, |x| +1 in [1,3]`
` :. sin (|x|+1) in [sin 3,1]`
Hence, the range is `{-2, -1} cup [sin 3,1].`
Also, for `y in [sin 3,1], [y]=0,1.`
Hence, the number of integral points in the range is 4.