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The area of the figure bounded by the pa...

The area of the figure bounded by the parabola `(y-2)^2=x-1,` the tangent to it at the point with the ordinate `x=3,` and the `x-a xi s` is `7s qdotu n i t e s` (b) `6s qdotu n i t e s` `9s qdotu n i t e s` (d) None of these

A

3

B

6

C

9

D

12

Text Solution

Verified by Experts

The correct Answer is:
C
The given parabola is `(y-2)^(2)=x-1.` So
`(dy)/(dx)=(1)/(2(y-2))`
At(2,3),
`(dy)/(dx)=(1)/(2(3-2))=(1)/(2)`
Tangent at (2,3) is
`y-3=(1)/(2)(x-2) rArr x-2y+4=0`

Therefore, the required area
`=overset(3)underset(0)int[(y-2)^(2)+1]dy-overset(3)underset(0)int(2y-4)dy`
`=|((y-2)^(3))/(3)+y|_(0)^(3)-|y^(2)-4y|_(0)^(3)`
`=(1)/(3)+3+(8)/(3)-(9-12)`
`=9` sq. units
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