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Molecular formula of acetic acid is CH(3...

Molecular formula of acetic acid is `CH_(3) COOH.` Calculate its percentage composition by mass [ Given the atomic masses, `C = 12, H = 1, and O = 16`]

Text Solution

Verified by Experts

Molecular mass `= 2 xx 12 + 4 xx 1 + 2 xx 16`
` = 24 + 4 + 32 = 60`
Mass `% C = ( 2 4 xx 100 )/( 60 ) = 40`
Mass `% H = ( 4 xx 100)/( 60) = 6.66`
Mass `% O = ( 32 xx 100)/(60 )= 53. 33`
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  • Calcualte percentage composition of O atoms in CH_(3)COOH .

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