(Take `C_(w)=4180 J kg^(-1) K^(-1))` A block of weight 5kg falls from a height of 5m into a bucket containing 10L of water. If all the mechanical energy of the block is used to heat water, find the rise in temperature of water. Take `g= 10ms^(-2)`

Water fall from a height 50m, If one third of its mechanical energy converted into heat what will be the rise in temperature of water

Water at Bhakra dam falls through a height of 210 m. Assuming that the whole of the energy due to fall is converted into heat, calculate the rise in temperature of water. Take J = 4.2 J cal^(-1) and g = 9.8 ms^(-2) .

In a water-fall the water falls from a height of 100 m . If the entire K.E. of water is converted into heat, the rise in temperature of water will be

A man of weight 50kg carries an object to a height of 20m in a time of 10s .The power used by the man in this process is 2000W then find the weight of the object carried by the man take g=10ms^(-2)

Two identical masses of 5 kg each fall on a wheel from a height of 10 m . The wheel disturbs a mass of 2 kg water, the rise in temperature of water will be :-

Water falls from a height 500m , what is the rise in temperature of water at bottom if whole energy remains in the water ? (J=4.2)

A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel =460 K//kg^(@)//C,g=10 m//s^(2) )