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A photon of frequency 5 xx 10^(14)Hz is ...

A photon of frequency `5 xx 10^(14)Hz` is incident on the surface of a metal. What is the energy of the incident photon in eV?

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A photon of frequency 5 xx 10^(14)Hz is incident on the surface of a metal. If the photoelectric thresh-old frequency for the metal is 3 xx 10^(14)Hz , Calculate the following Energy of the photon

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Knowledge Check

  • The threshold frequency for a certain metal for photoelectric effect is 1.7x10^(15)Hz . When light of frequency 2.2xx10^(15)Hz is incident on the metal surface, the kinetic energy of the emitted photoelectrons is 3.3xx10^(-19)J . What is the value of the Planck's constant ?

    A
    `3.3xx10^(-34)` J-s
    B
    `6.6xx10^(-34)` J-s
    C
    `8.6xx10^(-34)` J-s
    D
    `4xx10^(-35)` J-s

  • Work function of potassium metal is 2.30 eV . When light of frequency 8xx 10^(14) Hz is incident on the metal surface, photoemission of electrons occurs. The stopping potential of the electrons will be equal to

    A
    0.1 V
    B
    1.0 V
    C
    2.3 V
    D
    3.3 V

  • A photon of frequency v is incident on a metal surface whose threshold frequency is v_(0) . The kinetic energy of the emitted photoelectrons will be

    A
    hv
    B
    `hv_(0)`
    C
    `h(v+v_(0))`
    D
    `h(v-v_(0))`

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    The given graph shows the variation of KE with frequency of incident radiations for two surfaces A and B. (a) Which of the metals has greater work function ? For which of the metals will stopping potential be more for the same frequency of incident radiation ? (b) The work function caesium metal is 2.14 eV. When light of frequency 6xx10^(14) Hz. incident on the metal surface , what is the maximum KE of the photoelectrons and stopping potential ?

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    The work function of a surface is 3.1 eV. A photon of frequency 1x 10^(15) Hz. Is incident on it. Calculate the incident wavelength is photoelectric emission occur or not.

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