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1,2,3,……..,99,100 are called...

1,2,3,……..,99,100 are called

A

natural numbers

B

even numbers

C

odd numbers

D

prime numbers

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the series of numbers 1, 2, 3, …, 99, 100, we will analyze the options provided: natural numbers, even numbers, odd numbers, and prime numbers. ### Step-by-Step Solution: 1. **Identify the Series**: The given series is 1, 2, 3, …, 99, 100. This is a sequence of numbers starting from 1 and ending at 100. 2. **Understanding Natural Numbers**: Natural numbers are defined as the set of positive integers starting from 1 and going up to infinity. Therefore, the numbers 1, 2, 3, …, 100 are all natural numbers. 3. **Understanding Even Numbers**: Even numbers are those integers that are divisible by 2. In the given series, the even numbers would be 2, 4, 6, 8, …, 100. While some numbers in the series are even, not all numbers are even. 4. **Understanding Odd Numbers**: Odd numbers are integers that are not divisible by 2. In the series, the odd numbers would be 1, 3, 5, 7, …, 99. Similar to even numbers, not all numbers in the series are odd. 5. **Understanding Prime Numbers**: Prime numbers are natural numbers greater than 1 that have no positive divisors other than 1 and themselves. Examples include 2, 3, 5, 7, 11, etc. Again, while some numbers in the series are prime, not all numbers are prime. 6. **Conclusion**: Since the entire series from 1 to 100 consists of natural numbers, the correct answer to the question is that the numbers 1, 2, 3, …, 99, 100 are called **natural numbers**. ### Final Answer: The numbers 1, 2, 3, …, 99, 100 are called **natural numbers**.
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Knowledge Check

  • If the average of the numberd ,1,2,3 ….. 98,99 x is 100 x then the value of x is

    A
    `(51 )/(100)`
    B
    `(50 )/(99)`
    C
    `(50 )/(101)`
    D
    `(51)/(99)`
  • [[-(1)/(3)]+[-(1)/(3)-(1)/(100)]+[-(1)/(3)-(2)/(100)]+...+[-(1)/(3)-(99)/(100)] is equal to (where [.] denotes greatest integer function)

    A
    `-132`
    B
    `-133`
    C
    `-134`
    D
    `-131`
  • An equation a_(0) + a_(2)x^(2) + "……" + a_(99)x^(99) + x^(100) = 0 has roots .^(99)C_(0), .^(99)C_(1), C_(99)C_(2), "…..", .^(99)C_(99) The value of (.^(99)C_(0))^(2) + (.^(99)C_(1))^(2) + "….." + (.^(99)C_(99))^(2) is equal to

    A
    `2a_(98) - a_(99)^(2)`
    B
    `a_(99)^(2) - a_(98)`
    C
    `a_(99)^(2) - 2a_(98)`
    D
    none of these
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