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Equation of the line passing through the...

Equation of the line passing through the point `(acos^(3)theta, a sin^(3)theta)` and perpendicular to the line `x sec theta+y cos theta=a` is
`x cos theta-y sin theta=a sin 2 theta`.

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The equation to the straight line passing through the point (a cos^(3)theta,a sin^(3)theta) and perpendicular to the line x sec theta+y csc theta=a is x cos theta-y sin theta=a cos2 thetax cos theta+y sin theta=a cos2 thetax sin theta+y cos theta=a cos2 theta none of these

Equation of the line passing through the point (acos^3theta, a sin^3theta) and perpendicular to the line xsectheta + y cosec theta =a is xcostheta-ysintheta =acos2theta .

Knowledge Check

  • The equation to the straight line passing through the point (a "cos"^(3) theta, a "sin"^(3) theta) and perpendicular to the line x "sec" theta + y"cosec" theta = a is

    A
    `x "cos " theta-y "sin" theta = a "cos" 2theta`
    B
    `x "cos " theta+y "sin" theta = a "cos" 2theta`
    C
    `x "sin" theta+y "cos" theta = a "cos" 2theta`
    D
    none of these
  • If p and p' the lengths of perpendicular from origin to the lines x sec theta-y cosec theta=axcos theta-y sin theta=a cos 2 theta, then 4p^(2)+p^('2)=

    A
    `4a^(2)`
    B
    `2a^(2)`
    C
    `a^(2)`
    D
    none
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    The equation of a straight line, which passes through the point (a cos^3 theta, a sin^3 theta) and perpendicular to x sec theta + y "cosec" theta = a , is

    Find the equation of the straight line through (a cos theta, b sin theta) perpendicular to the line x/(a cos theta)+ y/(b sin theta) = 1 .

    x = "cos" theta - "cos" 2 theta, y = "sin" theta - "sin" 2 theta

    Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

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