Home
Class 12
MATHS
Let omega be a complex cube root of unit...

Let `omega` be a complex cube root of unity with `omega!=1a n dP=[p_(i j)]` be a `nxxn` matrix withe `p_(i j)=omega^(i+j)dot` Then `p^2!=O ,w h e nn=` a.`57` b. `55` c. `58` d. `56`

A

`50`

B

`55`

C

`56`

D

`58`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
Promotional Banner

Topper's Solved these Questions

  • EXAMINATION PAPER -2013

    ML KHANNA|Exercise PAPER -II SECTION-2 (PARAGRAPH TYPE)|8 Videos

  • EXAMINATION PAPER -2013

    ML KHANNA|Exercise PAPER -II SECTION-3 (MATCHING LIST TYPE)|4 Videos

  • EXAMINATION PAPER -2013

    ML KHANNA|Exercise PAPER -I SECTION-3 (INTEGER VALUE CORRECT TYPE)|5 Videos

  • DIFFERENTIATION

    ML KHANNA|Exercise MESCELLANEOUS EXERCISE|3 Videos

  • EXAMINATION PAPER-2014 (IIT-JEE-MAIN)

    ML KHANNA|Exercise Multiple Choice Question |30 Videos

Similar Questions

Explore conceptually related problems

Let omega be a complex cube root of unity with omega!=1 and P=[p_(ij)] be a n xx n matrix withe p_(ij)=omega^(i+j). Then p^(2)!=O, when n=a..57b 55c.58d.56

Let omega be a complex cube root of unity with omega ne 0 and P=[p_(ij)] be an n x n matrix with p_(ij)=omega^(i+j) . Then p^2ne0 when n is equal to :

Let omega be a complex cube root of unity with omegane1 and P = [p_ij] be a n × n matrix with p_(ij) = omega^(i+j) . Then P^2ne0, , when n =

If omega!=1 is a cube root of unity,then roots of (x-2i)^(3)+i=0

If omega!=1 is the complex cube root of unity and matrix H=[[omega,00,omega]], then H^(70) is equal to

If omega is a complex cube root of unity then the matrix A = [(1, omega^(2),omega),(omega^(2),omega,1),(omega,1,omega^(2))] is a

If omega is the cube root of unity, then what is the con jugate of 2omega^(2)+3i ?

If omega is the complex cube root of unity then 1quad 1+i+omega^(2),omega^(2)1-i,-1-iquad -i+omega-1]|=