Answer
Step by step text solution for If arcs of same length in two circles subtend angles of 60^(@)" and " 75^(@) at their centers, find the ratios of their radii. by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.
|
Topper's Solved these Questions
TRIGONOMETRIC EQUATION
ALLEN|Exercise All Questions|114 VideosView Playlist
Similar Questions
Explore conceptually related problems
Knowledge Check
Similar Questions
Explore conceptually related problems
ALLEN-TRIGONOMETRIC RATIOS AND IDENTITIES-All Questions
- If arcs of same length in two circles subtend angles of 60^(@)" and " ...
01:34
|
Playing Now - If sintheta+sin^2theta=1, then prove that cos^(12)theta+3cos^(10) thet...
02:58
|
Play - about to only mathematics
03:31
|
Play - If sintheta=-1/2a n d\ t a ntheta=1/(sqrt(3))t h e n\ theta is equal t...
03:13
|
Play - Show that sqrt(3)\ cos e c\ 20^0-sec20^0=4.
03:20
|
Play - Prove that: t a n 70^0=t a n 20^0+2t a n 50^0dot
04:22
|
Play - If sin 2A=lambda sin 2B, prove that : (tan (A+B))/(tan(A-B)) = (lambda...
02:41
|
Play - (sin5theta+sin2theta-sin tehta)/(cos5theta+2cos3theta+2cos^(2)theta+co...
03:31
|
Play - Prove that: s in 12^0s in 48^0s in 54^0=1/8dot
04:55
|
Play - Show that : tan (60^0 + A). Tan (60^0 -A) = (2 cos 2A+1)/(2cos 2A-1)
07:16
|
Play - Prove that :t a n A+tan(60^0+A)+tan(120^0+A)=3t a n3A
04:19
|
Play - sin (67(1)/2)^(@)+cos(67(1)/2)^(@) is equal to
04:02
|
Play - The value of sin 78^0-sin 66^0-sin 42^0+sin6^0 is a. -1 b. 1//2 c. -1/...
03:37
|
Play - In any triangle A B C ,\ sin A-cos B=cos C ,\ the angle\ B is a.pi...
05:25
|
Play - If A+B+C=(3pi)/2, t h e ncos2A+cos2B+cos2C is equal to 1-4cos Acos Bc...
05:09
|
Play - Prove that 5 cos theta+3cos(theta+(pi)/(3))+3 lies between -4 and 10.
05:05
|
Play - Find the maximum value of 1+sin((pi)/(4)+theta) +2sin ((pi)/(4)-thet...
04:09
|
Play - Prove that t a n A+2t a n2A+4t a n4A+8cot8A=cot Adot
04:33
|
Play - sum(r=1)^(n-1)cos^(2) (rpi)/2 is equal to
11:37
|
Play - Prove that: (1+sec2theta)(1+sec4theta)(1+sec8theta)(1+sec2^ntheta)=t a...
08:49
|
Play