Find the `% w//v " of " ''10V'' H_(2)O_(2)` solution

Options

A. `10.2%`
B. `3.03%`
C. `22.4%`
D. `5.04%`

Explanation

To find the % w/v (weight/volume percentage) of a 10 V H₂O₂ solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Volume Strength**:
The term "10 V" means that 1 liter of the solution can release 10 liters of oxygen gas at standard conditions when decomposed.

2. **Determine Molarity**:
The molarity (M) of the solution can be calculated using the formula:
\[ \text{Molarity} = \frac{\text{Volume Strength}}{11.35} \]
For a 10 V solution:
\[ \text{Molarity} = \frac{10}{11.35} \approx 0.881 \, \text{M} \]

3. **Find Molar Mass of H₂O₂**:
The molar mass of hydrogen peroxide (H₂O₂) is calculated as follows:
- Hydrogen (H): 1 g/mol × 2 = 2 g/mol
- Oxygen (O): 16 g/mol × 2 = 32 g/mol
- Total molar mass of H₂O₂ = 2 + 32 = 34 g/mol

4. **Calculate % w/v**:
The formula for weight/volume percentage is:
\[ \% \text{ w/v} = \left( \text{Molarity} \times \text{Molar Mass of Solute} \right) \div 10 \]
Plugging in the values:
\[ \% \text{ w/v} = \left( 0.881 \, \text{M} \times 34 \, \text{g/mol} \right) \div 10 \]
\[ \% \text{ w/v} = \left( 29.974 \right) \div 10 \approx 2.9974 \% \]
Rounding this to two decimal places gives us:
\[ \% \text{ w/v} \approx 3\% \]

### Final Answer:
The % w/v of the 10 V H₂O₂ solution is approximately **3%**.