A solution of copper (II) sulphate is electrolysed between copper electrodes by a current of `10.0` amperes passing for one hour. What changes occur at the electrodes and in the solution?

Explanation

To solve the problem of what changes occur at the electrodes and in the solution during the electrolysis of copper (II) sulfate between copper electrodes, we can follow these steps:

### Step 1: Understand the Electrolysis Process
Electrolysis involves the decomposition of a compound in solution using an electric current. In this case, we are using copper (II) sulfate (CuSO₄) in an aqueous solution with copper electrodes.

### Step 2: Convert Time to Seconds
The current is given as 10.0 amperes and it is passed for 1 hour. We need to convert the time into seconds for calculations:
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