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A 0.2 molal aqueous solution of a weak a...

A `0.2` molal aqueous solution of a weak acid `HX` is `20%` ionized. The freezing point of the solution is `(k_(f) = 1.86 K kg "mole"^(-1)` for water):

A

`-0.45^(@)C`

B

`-0.9^(@)C`

C

`-0.31^(@)C`

D

`-0.53^(@)C`

Text Solution

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The correct Answer is:
To solve the problem of finding the freezing point of a 0.2 molal aqueous solution of a weak acid \( HX \) that is 20% ionized, we will follow these steps: ### Step 1: Calculate the degree of ionization The degree of ionization \( \alpha \) is given as 20%, which can be expressed as: \[ \alpha = \frac{20}{100} = 0.2 \] ### Step 2: Determine the van 't Hoff factor \( i \) For the weak acid \( HX \), it ionizes into \( H^+ \) and \( X^- \). This means that for every mole of \( HX \), we get 2 moles of ions. The van 't Hoff factor \( i \) can be calculated using the formula: \[ i = 1 + (\alpha \cdot (n - 1)) \] where \( n \) is the number of ions produced. Here, \( n = 2 \) (since \( HX \) produces \( H^+ \) and \( X^- \)): \[ i = 1 + (0.2 \cdot (2 - 1)) = 1 + 0.2 = 1.2 \] ### Step 3: Calculate the freezing point depression \( \Delta T_f \) The formula for freezing point depression is given by: \[ \Delta T_f = i \cdot K_f \cdot m \] where: - \( K_f = 1.86 \, \text{K kg mole}^{-1} \) (freezing point depression constant for water) - \( m = 0.2 \, \text{molal} \) Substituting the values: \[ \Delta T_f = 1.2 \cdot 1.86 \cdot 0.2 \] Calculating this gives: \[ \Delta T_f = 1.2 \cdot 1.86 \cdot 0.2 = 0.4464 \, \text{K} \] ### Step 4: Calculate the freezing point of the solution The freezing point of pure water \( T_f \) is 0°C. The freezing point of the solution \( T_f' \) can be calculated using: \[ T_f' = T_f - \Delta T_f \] Substituting the values: \[ T_f' = 0 - 0.4464 = -0.4464 \, \text{°C} \] ### Final Answer The freezing point of the solution is approximately: \[ T_f' \approx -0.45 \, \text{°C} \] ### Summary of Steps 1. Calculate the degree of ionization \( \alpha \). 2. Determine the van 't Hoff factor \( i \). 3. Calculate the freezing point depression \( \Delta T_f \). 4. Calculate the freezing point of the solution \( T_f' \).

To solve the problem of finding the freezing point of a 0.2 molal aqueous solution of a weak acid \( HX \) that is 20% ionized, we will follow these steps: ### Step 1: Calculate the degree of ionization The degree of ionization \( \alpha \) is given as 20%, which can be expressed as: \[ \alpha = \frac{20}{100} = 0.2 \] ...
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