Home
Class 12
PHYSICS
In a YDSE experiment two slits S(1) and ...


In a YDSE experiment two slits `S_(1)` and `S_(2)` have separation of d=2mm the distance of the screen is `D=(8)/(5)` m source S starts moving from a very large distance towards `S_(2)` perpendicular to `S_(1)S_(2)` as shown in figure the wavelength of monochromatic light is 500 nm. The number of maximas observed on the screen at point P as the moves towards `S_(2)` is

A

4001

B

3999

C

3998

D

4000

Text Solution

Verified by Experts

The correct Answer is:
D
`S_(1)P-S_(2)P=(d^(2))/(2D)=(2xx10^(-3)xx2xx0^(-3))/(2xx(8)/(5))=(5)/(2)lamda" "(lamda=500nm)`
So when S is at `infty` there is `1^(st)` minima and when S is at `S_(2)` there is last minima because `d//lamda=4000`
So the number of minima's will be 4001 and number of maxima's will be 4000.
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    ALLEN|Exercise Example 9|1 Videos

  • WAVE OPTICS

    ALLEN|Exercise Example 10|1 Videos

  • WAVE OPTICS

    ALLEN|Exercise Example 7|1 Videos

  • UNIT & DIMENSIONS, BASIC MATHS AND VECTOR

    ALLEN|Exercise Exercise (J-A)|7 Videos

Similar Questions

Explore conceptually related problems

Two coherent sources S_(1)" and "S_(2) are separated by a small distance d. The fringes obtained on the screen will be:

Two coherent point sources S_1 and S_2 are separated by a small distance d as shown. The fringes obtained on the screen will be

Two coherent point sources S_1 and S_2 are separated by a small distance d as shown. The fringes obtained on the screen will be

In the arrangement shown in Fig., slits S_(1) and S_(4) are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S_(1) S_(2) and S_(3) S_(4) . If a hole is made at O' on AO' O and the slit S_(4) is closed, then the ratio of the maximum to minimum observed on screen at O , if O' S_(3) is equal to (lambda D)/(4d) , is

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is:

If S_1 and S_2 are two point sources emitting light in phase , then what is the shape of interference fringes formed on the screen ?

In the given figure ,C is middle point of line S_(1)S_(2) .A monochromatic light of wavelength gamma is incident on slits.The ratio of intensites of S_(3) and S_(4) is

In a Young's double slit experiment, let S_(1) and S_(2) be the two slits, and C be the centre of the screen. If angle S_(1)CS_(2)=theta and lambda is the wavelength, the fringe width will be

In a Young's double slit experiment, the slit separation is 1mm and the screen is 1m from the slit. For a monochromatic light of wavelength 500nm , the distance of 3rd minima from the central maxima is

In the arrangement shown in Fig., slits S_(1) and S_(4) are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S_(1) S_(2) and S_(3) S_(4) . The minimum value of Z for which the intensity at O is zero is