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Two beams of light having intensities I and 4I intefere to produce a fringe pattern on a screen. The phase difference between the beams is `pi // 2` at point A and `pi` at point B. Then the difference between the resultant intensities at A and B is

A

2I

B

4I

C

5I

D

7I

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(A)=I+4I+2sqrt(4I^(2))cos((pi)/(2))=5I`
`I_(B)=I+4I+2sqrt(4I^(2))cospi=I`
So difference `I_(A)-I_(B)=4I`
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Knowledge Check

  • Two beam of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is (pi)/(2) at point A and pi at point B. Then the difference between resultant intensities at A and B is : (2001 , 2M)

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    B
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